javascript实现多边形碰撞检测
#代码知识 发布时间: 2026-01-12
javascript多边形碰撞检测

原理就是 循环每个顶点判断是不是在多边形内
const app = new PIXI.Application({ antialias: true });
document.body.appendChild(app.view);
const graphics = new PIXI.Graphics();
// draw polygon
const path = [600, 370, 700, 460, 780, 420, 730, 570, 590, 520];
graphics.lineStyle(0);
graphics.beginFill(0x3500FA, 1);
graphics.drawPolygon(path);
graphics.endFill();
app.stage.addChild(graphics);
var xuanzhuan = PIXI.Sprite.from('/moban/images/share.jpg');
xuanzhuan.width=120;
xuanzhuan.height=120;
xuanzhuan.x=13;
xuanzhuan.y=33;
app.stage.addChild(xuanzhuan);
xuanzhuan.interactive = true;
xuanzhuan.buttonMode = true;
xuanzhuan
.on('pointerdown', onDragStart)
.on('pointerup', onDragEnd)
.on('pointerupoutside', onDragEnd)
.on('pointermove', onDragMove);
function onDragStart(event) {
// store a reference to the data
// the reason for this is because of multitouch
// we want to track the movement of this particular touch
this.data = event.data;
this.alpha = 0.5;
this.dragging = true;
}
function onDragEnd() {
this.alpha = 1;
this.dragging = false;
// set the interaction data to null
this.data = null;
}
var posPolygon=[];
var dianlist={};
dianlist['x']=600;
dianlist['y']=370;
posPolygon.push(dianlist)
var dianlist={};
dianlist['x']=700;
dianlist['y']=460;
posPolygon.push(dianlist)
var dianlist={};
dianlist['x']=780;
dianlist['y']=420;
posPolygon.push(dianlist)
var dianlist={};
dianlist['x']=730;
dianlist['y']=570;
posPolygon.push(dianlist)
var dianlist={};
dianlist['x']=590;
dianlist['y']=520;
posPolygon.push(dianlist)
function onDragMove() {
if (this.dragging) {
const newPosition = this.data.getLocalPosition(this.parent);
this.x = newPosition.x;
this.y = newPosition.y;
var baoweihe=this.getBounds();
var youxiajiaox=baoweihe.x+baoweihe.width;
var youxiajiaoy=baoweihe.y+baoweihe.height;
var poslist=[];
var pos={};
pos['x']=baoweihe.x;
pos['y']=baoweihe.y;
poslist.push(pos);
var pos={};
pos['x']=youxiajiaox;
pos['y']=baoweihe.y;
poslist.push(pos);
var pos={};
pos['x']=youxiajiaox;
pos['y']=youxiajiaoy;
poslist.push(pos);
var pos={};
pos['x']=baoweihe.x;
pos['y']=youxiajiaoy;
poslist.push(pos);
var ispengzhuang=PolygonInPolygon(poslist, posPolygon,5);
if(ispengzhuang){
alert('碰撞了');
}
}
}
function PolygonInPolygon(posPolygonA, posPolygonB, count){
console.log(posPolygonA);
var count1=posPolygonA.length;
for(var i=0;i<count1;i++ ){
var pos=posPolygonA[i];
console.log(pos);
var ispengzhuang=PointInPolygon( pos, posPolygonB, count);
if(ispengzhuang){
alert('碰撞了')
}
}
}
function PointInPolygon( pos, posPolygonB, count)
{
var cross = 0; //交点个数
for( var i = 0; i < count; i++ )
{
var p1 = posPolygon[i];
var p2 = posPolygon[(i + 1) % count]; //下一个节点
// p1p2这条边与水平线平行
if( p1.y == p2.y )
continue;
// 交点在p1p2的延长线上
if( pos.y < Math.min( p1.y, p2.y ) )
continue;
// 交点在p1p2的延长线上
if( pos.y > Math.max( p1.y, p2.y ) )
continue;
// 计算交点 X 左边 : (p2.y - p1.y)/(p2.x - p1.x) = (y - p1.y)/(x - p1.x)
// 直线 K 值相等, 交点y = pos.y
let x = (pos.y - p1.y) * (p2.x - p1.x) / (p2.y - p1.y) + p1.x
// 只统计单边交点,即点的正向方向
if(x > pos.x)
cross ++;
}
return cross % 2 == 1;
}
以上就是javascript实现多边形碰撞检测的详细内容,更多关于javascript多边形碰撞检测的资料请关注其它相关文章!
代码知识SEO上一篇 : Python Tkinter实例——模拟掷骰子
下一篇 : JavaScript如何操作css
-
SEO外包最佳选择国内专业的白帽SEO机构,熟知搜索算法,各行业企业站优化策略!
SEO公司
-
可定制SEO优化套餐基于整站优化与品牌搜索展现,定制个性化营销推广方案!
SEO套餐
-
SEO入门教程多年积累SEO实战案例,从新手到专家,从入门到精通,海量的SEO学习资料!
SEO教程
-
SEO项目资源高质量SEO项目资源,稀缺性外链,优质文案代写,老域名提权,云主机相关配置折扣!
SEO资源
-
SEO快速建站快速搭建符合搜索引擎友好的企业网站,协助备案,域名选择,服务器配置等相关服务!
SEO建站
-
快速搜索引擎优化建议没有任何SEO机构,可以承诺搜索引擎排名的具体位置,如果有,那么请您多注意!专业的SEO机构,一般情况下只能确保目标关键词进入到首页或者前几页,如果您有相关问题,欢迎咨询!